Find the domain of the following real functions :
(i) $f (x) = \sqrt{16 - x^{2}}$

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Solution

The function is defined only when $16 - x^{2} \geq 0 x^{2} \leq 16 | x | \leq 4 x \in [- 4, 4]$

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Find the domain of the following real functions :(i)f(x)=√16−x2

The function is defined only when 16−x2≥0x2≤16|x|≤4x∈[−4,4]

Find the domain of the following real functions :
(i) $f (x) = \sqrt{16 - x^{2}}$

The function is defined only when $16 - x^{2} \geq 0 x^{2} \leq 16 | x | \leq 4 x \in [- 4, 4]$