Find the domain of the function $f$ defined by $f (x) = s q r t (x^{2} + 1) + 2$ where sqrt is the square root.

R - {2}

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R

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2

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R - {1}

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Solution

The correct option is A $R$
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Hence the domain of $f (x) = s q r t (x^{2} + 1) + 2$ is set of all real numbers.

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