Find the eccentricity of hyperbola y29-x216-1-

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Standard XII

Mathematics

General Equation of Parabola

Find the ecce...

Question

Find the eccentricity of hyperbola $\frac{y^{2}}{9} - \frac{x^{2}}{16} = 1$ .

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Solution

In the above equation,
$a = 3, b = 4$
And,
$c^{2} = a^{2} + b^{2} = 9 + 16 = 25$
So, $c = 5$
Then, $e = \frac{c}{a} = \frac{5}{3}$

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Find the eccentricity of hyperbola y29−x216=1.

In the above equation,a=3,b=4And,c2=a2+b2=9+16=25So, c=5Then, e=ca=53

Find the eccentricity of hyperbola $\frac{y^{2}}{9} - \frac{x^{2}}{16} = 1$ .

In the above equation,
$a = 3, b = 4$
And,
$c^{2} = a^{2} + b^{2} = 9 + 16 = 25$
So, $c = 5$
Then, $e = \frac{c}{a} = \frac{5}{3}$