Question

Find the effort required to lift a load of $50kgwt$ using a simple machine.

Answer 1

Given data:

Load of the simple machine, $W=50kgwt$

Finding the effort required to lift the load:

In the case of one fixed pulley:

1. In this type of pulley the effort applied is equal to the load.
2. Thus, its mechanical advantage is equal to one.$\Rightarrow Mechaincaladvantage(M.A)=\frac{W}{P}=1$, Where $W$ is the load and $P$ is the effort.
3. So, if we use one fixed pulley, the effort required to lift the load will $50kgwt$ in one direction.

In the case of single movable pulley:

• In single movable pulley $Mechanicaladvantage(M.A)=\frac{W}{P}=\frac{2P}{P}=2i.e.W=2P$.
• So , $EffortP=\frac{W}{2}=\frac{50}{2}=25kgwt$.
• Hence, if we use a single moving pulley, the effort will be $25kgwt$.