In the given A.P., we have:
a = 1 and d = t2 – t1 = 7 – 1 = 6
We know that the nth term of an A.P. is tn = a + (n – 1)d.
To find the 18th term of the given A.P., we need to take n = 18.
Thus, we have:
t18 = 1 + (18 – 1)6
= 1 + 17 × 6
= 1 + 102
= 103
Therefore, the 18th term of the given A.P. is 103.