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Question

# Find the electric field at a given point ‘O’ due to a semi-circular charged ring having linear charge density λ.

A

λ4πε0r

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B

λ2ε0r

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C

λ2πε0r

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D

λ4πε0r2

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Solution

## The correct option is C λ2πε0r We know that the electric field due to a circular arc at a point on its Centre E = λ2πε0rsinα2 where α is the angle subtended at the Centre. Here the angle subtended at the Centre is π [It’s ok if you don’t remember this, I recommend you to watch the derivation video once again] So E = λ2πε0rsinπ2 = λ2πε0r

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