Question

Find the eleventh term from the last term of the AP.
$27,23,19,.........-65$.

Answer 1

$27,23,19,..........,-65$

If we reverse the series

$1^{st}$ term $=-65$

Last term $=27$

$=>d=\pm 4$

$t_{11}=-65+(11-4)4$

$=-65+40=-25$