Find the empirical formula of a compound containing 17.7 % hydrogena and 82.3 % nitrogen.

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Solution

1.Compound contains 17.7% hydrogen and 82.3% Nitrogen
i.e if 100g of the compound is present, 17.7g of Hydrogen and 82.3g of Nitrogen is present

2. Converting the weight into number of moles of each element: We divide the mass of each element by the molar mass
Moles of hydrogen = $fraction numerator 17.7 over denominator 1 end fraction$
Moles of Nitrogen = $fraction numerator 82.3 over denominator 14 end fraction equals 5.88$

3. We divide the mole value obtained by the smallest number ;
i.e
$N space colon space H fraction numerator 5.88 over denominator 5.88 end fraction colon fraction numerator 17.7 over denominator 5.88 end fraction 1 space space space space space colon space space space 3$

Hence the formula of the compound is

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