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Question

Find the empirical formula of iron oxide which has 69.9% of Fe and 30% of oxygen by mass.

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Solution

Consider 100 gm of the oxide,
Mass of Fe=69.9gm
Moles of Fe=69.656=1.248
Mass of oxygen =30gm
Moles of oxygen =3016=2.5
Empirical formula =Fe1.298O2.5
=FeO2
[dividing by 1.298]

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