Find the empirical formula of the compounds with the following percentage composition.
Pb = 62.5%; N = 8.5 %. O = 29.0%

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Solution

Element % At. mass Atomic ratio simple ratio

Pb 62.5 207 $\frac{62.5}{207} = 0.3019$ 1

N 8.5 14 $\frac{8.5}{14} = 0.6071$ 2

O 29 16 $\frac{29}{16} = 1.81$ 6

so

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A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of the compound. [Pb = 207, O = 16]

P b = 90.66 %; O = 9.34 %

[P b = 207; O = 16]

N = 25.94 %

= 74.06 %

An organisc compound, whose vapour density is 45, has the following percentage composition,
H = 2.22 % O = 71 . 19% and remaining carbon.

Calculate:
(a) its empirical formula, (b) its molecular formula.

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