Find the energy, the frequency and the momentum of an X-ray photon of wavelength 0.10 nm.

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Solution

Given $λ$ = 0.1 nm

(a) Energy = $\frac{h c}{λ}$

= $\frac{1242 e V n m}{0.1 n m}$

= 12420 eV

= 12.42 KeV

= 12.42 KeV

$\approx$ 12.4 KeV

(b) Frequency = $\frac{c}{λ} = \frac{3 \times 10^{8}}{0.1 \times 10^{- 9}}$

= $3 \times 10^{8}$ Hz

(c) Momentum

$\frac{E}{c} = \frac{12.4 \times 10^{3} \times 1.6 \times 10^{- 19}}{3 \times 10^{8}}$

= 6.613 $\times 10^{- 24}$ Kg - m/s

= 6.62 $\times 10^{- 24}$ Kg - m/s

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Find the energy, the frequency and the momentum of an X-ray photon of wavelength 0.10 nm.

Given λ = 0.1 nm (a) Energy = hcλ = 1242 eV nm0.1 nm = 12420 eV = 12.42 KeV = 12.42 KeV ≈ 12.4 KeV (b) Frequency = cλ=3×1080.1×10−9 = 3×108 Hz (c) Momentum Ec=12.4×103×1.6×10−193×108 = 6.613 ×10−24 Kg - m/s = 6.62 ×10−24 Kg - m/s