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Enthalpy

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Question

Find the Entropy change in an isothermal expansion of one mole of an ideal gas from volume $V_{1}$ to $V_{2}$ .

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Solution

For isothermal expansion, T = constant
Heat absorbed by gas, $q_{r e v} = {- w}_{r e v} = 2.303 n R T log \frac{V_{f}}{V_{i}}$
Here, n = 1,
$V_{i} = V_{1} V_{f} = V_{2}$
Change in entropy, $Δ S = \frac{q_{r e v}}{T} Δ S = 2.303 R log \frac{V_{2}}{V_{1}}$

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