MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Enthalpy

Find the Entr...

Question

Find the Entropy change in an isothermal expansion of one mole of an ideal gas from volume $V_{1}$ to $V_{2}$ .

Open in App

Solution

For isothermal expansion, T = constant
Heat absorbed by gas, $q_{r e v} = {- w}_{r e v} = 2.303 n R T log \frac{V_{f}}{V_{i}}$
Here, n = 1,
$V_{i} = V_{1} V_{f} = V_{2}$
Change in entropy, $Δ S = \frac{q_{r e v}}{T} Δ S = 2.303 R log \frac{V_{2}}{V_{1}}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Suppose 4.00 mol of an ideal gas undergo a reversible isothermal expansion from volume

V_{1}

V_{2} = 2.00 V_{1}

at temperature T = 400 K. Find the entropy change of the gas. If the expansion is reversible and adiabatic instead of isothermal,what is the entropy change of the gas?

Q. The entropy change involved in the isothermal reversible expansion of

2

moles of an ideal gas from a volume of

10 {d m}^{3}

100 {d m}^{3}

27^{o} C

Q. The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from avolume of

10 d m^{3}

to a volume of 100

d m^{3}

27^{0} C

Q. The entropy change involved in the isothermal reversible expansion of 2 mole of an ideal gas from a volume of 10

d m^{3}

to a volume of 100

d m^{3}

27^{o} C

Q. The entropy change involved in the isothermal reversible expansion of

2

moles of an ideal gas from a volume of

10

^{3}

100

^{3}

27^{\circ} C

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon