Question

Find the equation locus of point, the sum of the square of its distance from the points $(2,5)$ and $(3,-1)$ is equal to $40$

Answer 1

let the point be $(x,y)$

Accord. to question $(x-2{)}^2+(y-5{)}^2+(x-3{)}^2+(y+1{)}^2=40$

locus will be $2x^2+2y^2-10x-8y=1$