Find the equation of a curve passing through the point (0,-2) given that at any point (x, y)on the curve the product of the slope of its tangent and y co-ordinate of the point is equal to the x co-ordinate of the point.
dydxy=x
⇒y dy=x dx⇒y2=x2+c−−(1)(0,−2)lies on (1)⇒4=c⇒y2=x2+4