Find the equation of a line passing through (2, 3) and inclined at an angle of 135∘ with the positive direction of x-axis
x + y - 5 = 0
Here, m = slope of a line
We know, m = tan 135∘ = tan(90∘ + 45∘) = - cot 45∘ = - 1
So, equation of the line is
y−y1=m(x−x1)
and (x1,y1) ⇒ (2, 3)
y - 3 = -1(x - 2)
y - 3 = - x + 2
x + y - 5 = 0
So, equation of the line is x + y - 5 = 0