Find the equation of a line passing through (2,−3) and inclined at an angle of 135o with the positive direction of x axis
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Solution
Here m = slope of the line = tan135∘=tan(90∘+45∘)=−cot45∘=−1,x1=2,y1=−3 So the equation of the line is y−y1=m(x−x1) i.e. y−(−3)=−1(x−2) or y+3=−x+2 or x+y+1=0