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Question

Find the equation of a line passing through point (5, 1) and parallel to the line 7x−2y+5=0.


A
7x2y+33=0
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B
7x2y33=0
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C
7x+2y33=0
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D
None
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Solution

The correct option is C 7x2y33=0
Given line are
7x2y+50
y=72x+52
slope=72

slope of required line =slope of given line=72

Equation of line passing though (5,1) is given by
y1=72(x5)

2y2=7x357x2y33=0

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