Question

Find the equation of a line passing through the point (2, 3) and parallel to the line 3x − 4y + 5 = 0.

Answer 1

The equation of the line parallel to 3x − 4y + 5 = 0 is $3x-4y+\lambda =0$, where $\lambda$ is a constant.

It passes through (2, 3).

$\therefore$$$\begin{gathered} 6-12+\lambda =0 \\ \Rightarrow \lambda =6 \end{gathered}$$

Hence, the required line is 3x − 4y + 6 = 0.