Find the equation of a line passing through the point (2, -3 ) and parallel to the line 2x - 3y + 8 = 0

2x - 3y =13

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2x -3y = 12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - 3y =4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3x - 2y = 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2x - 3y =13
Equation of the line parallel to $2 x - 3 y + 8 = 0$ will be of the form $2 x - 3 y + k = 0$
Now, since it passes through $(2, - 3)$ , on substituting it , we get $2 (2) - 3 (- 3) + k = 0$
$=> k = - 13$
So, required eqn of parallel line is $2 x - 3 y - 13 = 0$

Suggest Corrections

Similar questions

Find the equation of the line parallel to the line $3 x + 2 y = 8$ and passing through the point $(0, 1)$ .

The equation of the line parallel to the line 2x – 3y = 1 and passing through the middle point of the line segment joining the points (1, 3) and (1, –7), is:

Q. The equation of line passing through the point of intersection of the lines4x-3y-1=0 and 5x-2y-3=0 and parallel to the line 2y-3x+2=0, is

The equation of a straight line passing through the origin and perpendicular to the straight line 2x + 3y - 7 = 0 is ______.

Q. The asymptotes of a hyperbola have center at the point

(1, 2)

and are parallel to the lines

2 x + 3 y = 0

and

3 x + 2 y = 0

. If the hyperbola passes through the point

(5, 3)

, then its equation is

Join BYJU'S Learning Program

Find the equation of a line passing through the point (2, -3 ) and parallel to the line 2x - 3y + 8 = 0

The correct option is A 2x - 3y =13Equation of the line parallel to 2x−3y+8=0 will be of the form 2x−3y+k=0Now, since it passes through (2,−3), on substituting it , we get 2(2)−3(−3)+k=0=>k=−13So, required eqn of parallel line is 2x−3y−13=0

The correct option is A 2x - 3y =13
Equation of the line parallel to $2 x - 3 y + 8 = 0$ will be of the form $2 x - 3 y + k = 0$
Now, since it passes through $(2, - 3)$ , on substituting it , we get $2 (2) - 3 (- 3) + k = 0$
$=> k = - 13$
So, required eqn of parallel line is $2 x - 3 y - 13 = 0$