Question

Find the equation of a line passing through the point A(2, -3) and parallel to the line 2x - 3y + 6 = 0.

Answer 1

Here, $(x_1,y_1)=(2,-3),a=2$ and b = -3.
$\therefore$ Equation of the line passing through A (2, -3) and parallel to the line 2x - 3y + 6 = 0 is
$a(x-x_1)+b(y-y_1)=0.$ i.e., 2(x - 2) - 3(y + 3)
$=0\Rightarrow 2x-3y-130.$
Hence, the equation of the required line is 2x - 3y - 13 = 0