Find the equation of a line passing through the points A(3, -5) and (4, -8)

3x + y = 4

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3x + 2y = 5

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x + 3y = 4

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4x = 3y

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Solution

The correct option is C 3x + y = 4
Equation of line joining two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ is $y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$
So, equation of line joining $A (3, - 5); B (4, - 8)$ is $y + 5 = \frac{- 8 + 5}{4 - 3} (x - 3)$
$=> y + 5 = (- 3) (x - 3)$
$=>=> y + 5 = - 3 x + 9$
$=> 3 x + y = 4$

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Find the equation of the line passing through the point (-2, 3) and having y – intercept of 5 units.

Find the equation of the line passing through the points (2, 3) and the point of intersection of the lines $4 x - 3 y = 7$ and $3 x + 4 y + 1 = 0$ .

(i) Find the equation of the line passing through (5, -3) and parallel to x - 3y = 4.

(ii) Find the equation of the line parallel to the line 3x + 2y = 8 and passing through the point (0, 1).

A (3, - 5)

B (4, - 8)

Find the equation of a line with y – intercept = 5 & passing through the point (–4, 7).

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