Find the equation of a line passing through the points $A (3, - 5)$ and $B (4, - 8)$ .

3 x + y = 4

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3 x - y = 4

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3 x + y = - 4

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4 x = 3 y

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Solution

The correct option is A $3 x + y = 4$
Slope of line passing through the points $A (3, - 5)$ and $B (4, - 8)$ is
given by $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{- 8 - (- 5)}{4 - 3} = \frac{- 3}{1} = - 3$
Hence required equation of line is given by, $y - y_{1} = m (x - x_{1})$
$\Rightarrow y + 5 = - 3 (x - 3)$
$\Rightarrow 3 x + y = 4$

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Find the equation of the line passing through the points (2, 3) and the point of intersection of the lines $4 x - 3 y = 7$ and $3 x + 4 y + 1 = 0$ .

y = 3 x + 5

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x + y + 4 = 0

3 x - y - 8 = 0

x - 3 y = 0, 4 x + 3 y = 5

3 x + y = 0

3 x - 4 y = 0

3 x + 2 y = 6

(4, y)

y

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