Question

Find the equation of a line perpendicular to the line $x-2y+3=0$ and passing through the point $(1,-2)$.

Answer 1

Given 1. line $\Rightarrow x-2y+3=0$

$\Rightarrow y=\frac{1}{2}\left(x\right)+3/2$

slope = (1/2)

Then the slope of line ie. perpendicular line

should have slope (-2) also the line pass through (1,-2)

$\therefore$ eqution y+2= -2(x-1)

$\Rightarrow$ 2x+y=0