Find the equation of a line that cuts off equal intercepts on the cordinate axis and passes through the point (2, 3).

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Solution

Let equal intercepts on the coordinate axis be a and the line passes through point (2, 3).

$∴ \frac{2}{a} + \frac{3}{a} = 1 \Rightarrow a = 5$

Thus equation of required line is

$\frac{x}{5} + \frac{y}{5} = 1 \Rightarrow x + y = 5$ .

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Find the equation of a line that cuts off equal intercepts on the cordinate axis and passes through the point (2, 3).

Let equal intercepts on the coordinate axis be a and the line passes through point (2, 3). ∴ 2a+3a=1⇒ a=5 Thus equation of required line is x5+y5=1 ⇒ x+y=5.

Let equal intercepts on the coordinate axis be a and the line passes through point (2, 3).

$∴ \frac{2}{a} + \frac{3}{a} = 1 \Rightarrow a = 5$

Thus equation of required line is

$\frac{x}{5} + \frac{y}{5} = 1 \Rightarrow x + y = 5$ .