Find the equation of a line that has y-intercept 4 and is perpendicular to line joining (2, -3) and (4, 2).

2x + 5y - 20 = 0

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2x + 4y - 20 = 0

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5x + 2y - 20 = 0

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2x + 5y - 19 = 0

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Solution

The correct option is A 2x + 5y - 20 = 0
Given; $c = 4, S l o p e o f t h e l i n e p e r p e n d i c u l a r t o t h e g i v e n l i n e (m) = \frac{- (4 - 2)}{(2 + 3)} = \frac{- 2}{5} S o, y = \frac{- 2}{5} x + 4 \Rightarrow 2 x + 5 y - 20 = 0$

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Find the equation of a line which is perpendicular to the line joining (4, 2) and (3, 5) and cuts off an intercept of length 3 on y-axis.

Find the equation of a line that has y-intercept-4 and is parallel to the line joining (2, -5) and (1, 2).

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