Find the equation of a line which has the y-intercept 4, and is perpendicular to the line 2 – 3y = 7. Find the coordinates of the point where it cuts the -axis.

3 + 2y = 9, (3 , 0)

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3 – 2y = 8, (⁸/₃ , 0)

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– y = 8, (8 , 0)

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3 – 3y = 8, (⁸/₃ , 0)

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3 + 2y = 8, (⁸/₃ , 0)

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Solution

The correct option is E
3 + 2y = 8, (⁸/₃ , 0)

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Similar questions

Find the equation of line ⏊ to 4 + 3y = 5 & passing through the point where the line 5 – 6y = 30 cuts the – axis.

2 x + 3 y = 2, 3 x - 2 y = 4, x + 2 y = 3

2 x - y = 3

x - 2 y - 3 = 0

4 x + 3 y - 1 = 0

2

2 x - 3 y = 7

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