Find the equation of a line which passes through 5- 4 and makes an angle of 60- with the positive direction of the x-axis-

Slope of the line = tan 60^∘ = The line passes through the point (5, 4) = (x1, y1) Substituting the values in y y1 = m(x x1), we get, y 4 = (x 5) y 4 ...

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Standard X

Mathematics

Slope Intercept Form of a Straight Line

Find the equa...

Question

Find the equation of a line which passes through (5, 4) and makes an angle of $60^{\circ}$ with the positive direction of the x-axis.

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Solution

Slope of the line = tan $60^{\circ}$ =

The line passes through the point (5, 4) = (x₁, y₁)

Substituting the values in y - y₁ = m(x - x₁), we get,

y - 4 = (x - 5)

y - 4 = x - 5

y =x + 4 - 5, which is the required equation.

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Find the equation of a line which passes through (5, 4) and makes an angle of 60∘ with the positive direction of the x-axis.

Slope of the line = tan 60∘ = The line passes through the point (5, 4) = (x1, y1) Substituting the values in y - y1 = m(x - x1), we get, y - 4 = (x - 5) y - 4 = x - 5 y =x + 4 - 5, which is the required equation.

Find the equation of a line which passes through (5, 4) and makes an angle of $60^{\circ}$ with the positive direction of the x-axis.

Slope of the line = tan $60^{\circ}$ =

The line passes through the point (5, 4) = (x₁, y₁)

Substituting the values in y - y₁ = m(x - x₁), we get,

y - 4 = (x - 5)

y - 4 = x - 5

y =x + 4 - 5, which is the required equation.