Find the equation of a line with slope (m) = -3 and y - intercept (c) = -2.
y=-3x+2
y=3x-2
y=3x+2
y=-3x-2
The equation of a line in slope-intercept form is y=mx+c
Substituting m = -3 and c = -2, we get,
y=−3x−2
Hence (D)
The equations of the tangents drawn to the curve y2 - 2x3 - 4y + 8 = 0 from the point (1, 2) is... .