Question

Find the equation of a straight line passing through $(-1,-2)$ having slope $\frac{1}{3}$

Answer 1

Slope$=m=\frac{1}{3}$

The line passes through $(-1,-2)$

Equation of a line is $y-y_1=m(x-x_1)$

$y+2=\frac{1}{3}(x+1)$

$\Rightarrow 3y+6=x+3$

$\Rightarrow x-3y+3-6=0$

$\therefore x-3y-3=0$ is the required equation of a straight line.