Question

Find the equation of a straight line passing through $(-3,-1)$ having slope $\frac{-1}{2}$

Answer 1

Slope$=m=\frac{-1}{2}$

The line passes through $(-3,-1)$

Equation of a line is $y-y_1=m(x-x_1)$

$y+1=\frac{-1}{2}(x+3)$

$\Rightarrow 2y+2=-x-3$

$\Rightarrow 2y+2+x+3=0$

$\therefore x+2y+5=0$ is the required equation of a straight line.