Question

Find the equation of a straight line passing through $(4,-1)$ having slope $\frac{1}{4}$

Answer 1

Slope$=m=\frac{1}{4}$

The line passes through $(4,-1)$

Equation of a line is $y-y_1=m(x-x_1)$

$y+1=\frac{1}{4}(x-4)$

$\Rightarrow 4y+4=x-4$

$\Rightarrow x-4y-4-4=0$

$\therefore x-4y-8=0$ is the required equation of a straight line.