Question

Find the equation of a straight line passing through the points $(3,6)$ and $(-2,5)$

Answer 1

Equation of the line is $\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$

$\Rightarrow \frac{y-6}{x-3}=\frac{5-6}{-2-3}$

$\Rightarrow \frac{y-6}{x-3}=\frac{-1}{-5}$

$\Rightarrow \frac{y-6}{x-3}=\frac{1}{5}$

$\Rightarrow 5y-30=x-3$

$\Rightarrow x-5y-3+30=0$

$\therefore$ Equation of a line is $x-5y+27=0$