Question

Find the equation of a straight line passing through the points $(-4,7)$ and $(3,-6)$

Answer 1

Equation of the line is $\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$

$\Rightarrow \frac{y-7}{x+4}=\frac{-6-7}{3+4}$

$\Rightarrow \frac{y-7}{x+4}=\frac{-13}{7}$

$\Rightarrow 7y-49=-13x-52$

$\Rightarrow -13x-7y-52+49=0$

$\Rightarrow -13x-7y-3=0$

$\Rightarrow 13x+7y+3=0$

$\therefore$ Equation of a line is $13x+7y+3=0$