Question

Find the equation of a straight line passing through the points $(4,7)$ and $(3,6)$

Answer 1

Given Points $(4,7)$ and $(3,6)$

Equation of the line is $\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$

$\Rightarrow \frac{y-7}{x-4}=\frac{6-7}{3-4}$

$\Rightarrow \frac{y-7}{x-4}=\frac{-1}{-1}$

$\Rightarrow \frac{y-7}{x-4}=1$

$\Rightarrow y-7=x-4$

$\Rightarrow x-y-4+7=0$

$\therefore$ Equation of a line is $x-y+3=0$