Question

Find the equation of a straight line whose inclination is ${30}^{\circ }$ and $y-$ intercept is $5$

Answer 1

Given:$\theta ={30}^{\circ },y$-intercept$=5$

Slope$m=\tan \theta =\tan {30}^{\circ }=\frac{1}{\sqrt{3}}$

Equation of a line is $y=mx+c$

$y=\frac{1}{\sqrt{3}}x+5$

$\Rightarrow \sqrt{3}y=x+5\sqrt{3}$

Equation of line is $x-\sqrt{3}y+5\sqrt{3}=0$