Question

Find the equation of a straight line:
with slope $-1/3$ and $y-intercept$ $-4$.

Answer 1

Slope(m)$=\frac{-1}{3}$

y-intercept(i)$=-4$

$\therefore$ Straight line$\Rightarrow y=\frac{-1}{3}x-4$

$\Rightarrow 3y+x+12=0$