The equation of the given curve is,
y= 1 x−3 , x≠3
The slope of the tangent at any point ( x,y ) is given as,
Slope= dy dx
The slope of the given curve is,
dy dx = d( 1 x−3 ) dx = −1 ( x−3 ) 2
When the slope of the tangent is 2, then
−1 ( x−3 ) 2 =2 2 ( x−3 ) 2 =−1 ( x−3 ) 2 = −1 2
The above condition can never be satisfied for any value of x, so there is no tangent with slope 2 to the given curve.
Find the equation of all lines having slope 2 which are tangents to the curve.