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Question

Find the equation of chord of x2−y2=9 which is bisected at (5, -3).

A
5x + 3y + 16 = 0
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B
5x + 3y - 16 = 0
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C
3x + 5y + 16 = 0
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D
3x + 5y - 16 = 0
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Solution

The correct option is C 5x + 3y - 16 = 0
Equation of chord bisected at a given point is T=S
So the equation of chord of given hyperbola bisected at (5,3) is
x(5)y(3)9=(5)2(3)295x+3y=2595x+3y=165x+3y16=0
So option C is correct

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