Find the equation of circle passing through origin and concentric with $x^{2} + y^{2} - 8 x + 6 y + 10 = 0$ .

x^{2} + y^{2} - 8 x + 6 y = 0

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x^{2} + y^{2} - 8 x - 6 y = 0

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x^{2} + y^{2} + 8 x + 6 y = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + y^{2} + 8 x - 6 y = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is A $x^{2} + y^{2} - 8 x + 6 y = 0$

Equation of circle passing through origin
$r = \sqrt{{x_{1}}^{2} + {y_{1}}^{2}}$
${(x - x_{1})}^{2} + {(y - y_{1})}^{2} = {y_{1}}^{2}$
Given centre $(4, - 3)$
${(x - 4)}^{2} + {(y + 3)}^{2} = 1$
$x^{2} - 8 x + y^{2} + 6 y = 0$

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