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Byju's Answer
Standard XII
Mathematics
Parametric Equation of Parabola
Find the equa...
Question
Find the equation of hyperbola
whose center is
(
−
3
,
2
)
, one vertex is
(
−
3
,
4
)
and eccentricity is
5
2
.
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Solution
REF.Image.
a = distance b/w (3,2)& (-3,4)
a
=
√
(
4
−
2
)
2
=
2
Now,
b
2
=
a
2
(
e
2
−
1
)
=
4
(
25
4
−
1
)
=
21
e
q
n
of Hyperbola
(
x
+
3
)
2
4
−
(
y
−
2
)
2
21
=
1
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