Question

Find the equation of line joining the points $(1,-3)$ and $(4,-2).$

• A. x + y - 2 = 0
• B. 3x + y - 10 = 0
• C. x - 3y - 10 = 0
• D. x + y + 1 = 0

Answer 1

The correct option is C

x - 3y - 10 = 0

Consider $(x_1,y_1)=(1,-3)$ and $(x_2,y_2)=(4,-2)$

The equation of the line in two point form is given by:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$, where $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.

$y+3=\frac{-2+3}{4-1}(x-1)$

$y+3=\frac{1}{3}(x-1)$

$3y+9=x-1$

$x-3y-10=0$