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Question

Find the equation of line passing through (1,2) and parallel to 3x+5y+7=0

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Solution

The equation of line parallel to 3x+5y+7=0 is 3x+5y+k=0
The required line passes through (1,2)
So 3(1)+5(2)+k=03+10+k=013+k=0k=13
So the required line is 3x+5y13=0

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