Find the equation of line passing through $(4, - 2)$ and Parallel to $x - 7 y + 8 = 0$

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Solution

The equation of line that is parallel to $x - 7 y + 8 = 0$ is $x - 7 y + k = 0$
It passes through point $(4, - 2)$
$⟹ 4 - 7 (- 2) + k = 0 4 + 14 + k = 0 k = - 18$
The equation of line is $x - 7 y - 18 = 0$

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Find the equation of line passing through (4,−2) and Parallel to x−7y+8=0

The equation of line that is parallel to x−7y+8=0 is x−7y+k=0 It passes through point (4,−2)⟹4−7(−2)+k=04+14+k=0k=−18The equation of line is x−7y−18=0

Find the equation of line passing through $(4, - 2)$ and Parallel to $x - 7 y + 8 = 0$

The equation of line that is parallel to $x - 7 y + 8 = 0$ is $x - 7 y + k = 0$
It passes through point $(4, - 2)$
$⟹ 4 - 7 (- 2) + k = 0 4 + 14 + k = 0 k = - 18$
The equation of line is $x - 7 y - 18 = 0$