Question

Find the equation of line passing through point $(-1,-2)$ and perpendicular to $3x+4y-12=0$.

Answer 1

Equation of line perpendicular to the line $3x+4y=12$ is $4x-3y=c$.

Now this line passes through $(-1,-2)$ then,

$-4+6=c$

or, $c=2$.

So the equation of the line is $4x-3y=2$.