Find the equation of line passing through the point (1,-1) and making an angle $45^{o}$ with the positive direction of x-axis.

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Solution

Line passes through the point $(1, - 1)$ .
It makes an angle $45^{o}$ with the positive direction of x-axis. Therefore,
Slope, m = $tan 45^{o} = 1$
Equation of line is :
$y - y_{1} = m (x - x_{1})$
$y + 1 = 1 (x - 1)$
$y + 1 = x - 1$
$x - y - 2 = 0$

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Find the equation of line passing through the point (1,-1) and making an angle 45o with the positive direction of x-axis.

Line passes through the point (1,−1).It makes an angle 45o with the positive direction of x-axis. Therefore,Slope, m = tan45o=1Equation of line is :y−y1=m(x−x1)y+1=1(x−1)y+1=x−1x−y−2=0

Find the equation of line passing through the point (1,-1) and making an angle $45^{o}$ with the positive direction of x-axis.

Line passes through the point $(1, - 1)$ .
It makes an angle $45^{o}$ with the positive direction of x-axis. Therefore,
Slope, m = $tan 45^{o} = 1$
Equation of line is :
$y - y_{1} = m (x - x_{1})$
$y + 1 = 1 (x - 1)$
$y + 1 = x - 1$
$x - y - 2 = 0$