Dear Student,
Given line: x - 4y + 3 = 0
4y = x + 3
y =
Comparing it with : y = mx + c
Slope of line (m) =
Now, let the slope of perpendicular line be n, therefore
m * n = - 1
n =
n = - 4
Let the equation of line be y = nx + c
y = - 4x + c
When y = 0, x = 2
0 = - 4(2) + c
c = 8
Therefore, equation of line is: y = - 4x + 8
Regards