Find the equation of line which passes through a point $(0, 1)$ and intercept cut by line at x axis is three times the intercept cut at y-axis.

Open in App

Solution

Intercept form of straight line
$\frac{x}{a} + \frac{y}{b} = 1$ where a and b are intercepts

Now, Let y-intercept = p
So that the x-intercept = 3p

$\frac{x}{3 p} + \frac{y}{p} = 1$
as it pass through (0,1)
$\frac{0}{3 p} + \frac{1}{p} = 1 \Rightarrow p = 1$

Hence, Equation is $\frac{x}{3} + \frac{y}{1} = 1 \Rightarrow x + 3 y = 3$

Suggest Corrections

Similar questions

Q. The intercept cut off from y-axis is twice that from x-axis by the line and line is passes through (1, 2) then its equation is

If a line passes through the point (1, 2) and cuts off positive intercepts on the x–axis and y–axis in the ratio 2 : 3, find the equation of the line.

Find the equation of a line that cuts off equal intercepts on the cordinate axis and passes through the point (2, 3).

Q. Find the equation of line(s) which passes through the point

(22, - 6)

and whose intercept on the x-axis exceeds the intercept on y-axis by 5

Find equation of the line passing through the point (2, 2) and cutting off intercepts on the axis whose sum is 9.

Join BYJU'S Learning Program

Find the equation of line which passes through a point (0,1) and intercept cut by line at x axis is three times the intercept cut at y-axis.

Intercept form of straight line xa+yb=1 where a and b are interceptsNow, Let y-intercept = pSo that the x-intercept = 3px3p+yp=1as it pass through (0,1)03p+1p=1⇒p=1Hence, Equation is x3+y1=1⇒x+3y=3

Find the equation of line which passes through a point $(0, 1)$ and intercept cut by line at x axis is three times the intercept cut at y-axis.