Find the equation of line which passes through a point where line given by x-1 -1 - y-2 3 - z-4 6 cuts the x-axis and parallel to the line x 2 - y-1 3 - z-2 4

[ x 1 / 1 = y 2 / 3 = z 4 / 6 ...

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Byju's Answer

Standard XII

Mathematics

Angle between Two Line Segments

Find the equa...

Question

Find the equation of line which passes through a point where line given by $\frac{x - 1}{- 1} = \frac{y - 2}{3} = \frac{z - 4}{6}$ cuts the x-axis and parallel to the line $\frac{x}{2} = \frac{y + 1}{3} = \frac{z - 2}{4}$

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Solution

$\begin{matrix} \frac{x - 1}{- 1} = \frac{y - 2}{3} = \frac{z - 4}{6} (- r + 1, 3 r + 2, 6 r + 4) I t c u t s x - a x i s w h e n : 3 r + 2 = 0 r = - \frac{2}{3} (\frac{5}{3}, 0, 0) E q u a t i o n o f l i n e p a s sin g t h o u g h (\frac{5}{3}, 0, 0) a n d p a r a l l e l t o l i n e \frac{x}{2} = \frac{y + 1}{3} i s \frac{x - \frac{5}{3}}{2} = \frac{y - 0}{3} = \frac{z - 0}{4} \end{matrix}$

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Find the equation of line which passes through a point where line given by x−1−1=y−23=z−46 cuts the x-axis and parallel to the line x2=y+13=z−24

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Find the equation of line which passes through a point where line given by $\frac{x - 1}{- 1} = \frac{y - 2}{3} = \frac{z - 4}{6}$ cuts the x-axis and parallel to the line $\frac{x}{2} = \frac{y + 1}{3} = \frac{z - 2}{4}$