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Byju's Answer
Standard XI
Mathematics
Distance Formula
Find the equa...
Question
Find the equation of locus of a point equidistant from
A
(
2
,
0
)
and the
Y
−
axis.
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Solution
Let the point be
P
(
h
,
k
)
Given,
P
is equidistant from
A
(
2
,
0
)
and the
Y
axis
⇒
√
(
h
−
2
)
2
+
K
2
=
h
⇒
(
h
−
2
)
2
+
K
2
=
h
2
[Squaring]
⇒
h
2
+
4
−
4
h
+
K
2
=
h
2
⇒
K
2
=
4
(
h
−
1
)
Replacing
(
h
.
k
)
with
(
x
,
y
)
we get
y
2
=
4
(
x
−
1
)
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0
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