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Question

Find the equation of locus of a point equidistant from A(2,0) and the Y axis.

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Solution


Let the point be P(h,k)
Given,
P is equidistant from A(2,0) and the Y axis
(h2)2+K2=h
(h2)2+K2=h2 [Squaring]
h2+44h+K2=h2
K2=4(h1)
Replacing (h.k) with (x,y) we get
y2=4(x1)

1180899_1273898_ans_e75f6fc6e3eb4bfba139e3bcae2a468c.png

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