wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the equation of locus of point which is equidistant from (1,3) and x-axis.

Open in App
Solution

Let the point be (x,y)
Acord. to question (x1)2+(y3)2=y
locus will be x22x6y+10=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon